What is the center of the circle with this equation is (x+2)^2 +(y-4)^2=41

(-2,4)

Step-by-step explanation:

equation for a circle with radius r and center at (a,b):

(x-a)^2 + (y-b)^2 = r^2

your given equation rewritten in this form:

(x-(-2))^2 + (y-(4))^2 = 41

therefore, this cirlce has a center at (-2,4) and a radius of sqrt(41)

hope this helped! :)

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step-by-step explanation: