MATHSWATCH FUNCTIONS QUESTION CAN SOMEONE PLEASE HELP ME!!

Step-by-step explanation:

I'll use y instead of f(x):

The inverse of y [f(x)] = 3 - 5 is

x = 3 - 5

Rearrange to isolate y:

= (x+5)/3

For f(43) we get:

= (43+5)/3

= (48)/3

= 16

y = 4

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Since g(x) = x+1 and h(x)= x^2,

h(g(x)) = (x+1)^2

(x+1)^2

x^2 + 2x + 1

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This is set equal to 3x^2 + x - 5 and we can then solve for x:

3x^2 + x - 5 = x^2 + 2x + 1

2x^2 -x -6 = 0

(x-2)(2x+3) = 0

The solutions are:

x = -3/2 and x = 2