A college prep school advertises that their students are more prepared to succeed in college than other schools. To verify this, they categorize GPA's into 4 groups and look up the proportion of students at a state college in each category. They find that 7% have a 0-0. 99, 21% have a 1-1. 99, 37% have a 2-2. 99, and 35% have a 3-4. 00 in GPA. They then take a random sample of 200 of their graduates at the state college and find that 19 has a 0-0. 99, 28 have a 1-1. 99, 82 have a 2-2. 99, and 71 have a 3-4. 0. Can they conclude that the grades of their graduates are distributed differently than the general population at the school? Test at the 0. 05 level of significance.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

positive

step-by-step explanation:

the quadrant is facing upwards

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204