What is the amplitude, period, and phase shift of f(x) = −4 sin(2x + π) − 5? Amplitude = −4; period = 2π; phase shift: x = negative pi over two
Amplitude = −4; period = π; phase shift: x = pi over two
Amplitude = 4; period = π; phase shift: x = negative pi over two
Amplitude = 4; period = 2π; phase shift: x = pi over two

Hello, there!

»ANSWER«

What is the amplitude, period, and phase shift of f(x) = −4 sin(2x + π) − 5?

Amplitude = −4; period = 2π; phase shift: x = negative pi over two

Amplitude = −4; period = π; phase shift: x = pi over two

Amplitude = 4; period = π; phase shift: x = negative pi over two

Amplitude = 4; period = 2π; phase shift: x = pi over two

Amplatitude: - 4

K = 2; Period:

Phase shift: pi

#CarryOnLearning

1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

i hope this you, and have a wonderful day!

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.