From the top of a tower, the angle of depression to the bottom of a pillar on the same surface of height 20m is 60° If the a angle of depsession from the top of the . pillar to the bottom of the lower is 22. find the height of the tower. ( Ton 220 - 0,4)

Let AB=height of the building=100m

DE=AC=AB+BC=h= height of the tower

∠ADC=60

∘∠BDC=60 ∘

Now

tan30 ∘ = CDCB

= dx

31 = dx

(1)tan60 ∘ = CDCA

= dx+100

3 = dx+100

(2)From (1)d= 3

x (3)Substituting (3) in (2)

3 = 3 x(x+100)

3x=x+100

2x=100

x=50

Height of the tower=DE=h=AB+CB=100m+x=100m+50m=150m

refer to the attachment...

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the answer is d. (1.2, -4.7) on edgn

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