Very important question ☺️

130° is the correct answer

∠QPR=80°

∠PQR+∠QPR+∠QRP=180°

∠PQR+∠QRP=100°

2(x+y)=100°

x+y=50°

So, in △QOR

x+y+∠QOR=180°

∴∠QOR=180°−50°

=130°

130⁰

Step-by-step explanation:

Let,

<Q = x

<R = y

So,

In ∆PQR

2x + 2y + 80 = 180(Sum of all angle in a triangle is 180⁰)

2(x + y) = 180 - 80

2(x + y) = 100

x + y = 100/2

x + y = 50

Now,

In ∆QOR

x + y + QOR = 180(Sum of all angle in a triangle is 180⁰)

50 + QOR = 180

QOR = 180 - 50

QOR = 130⁰

the answer is ! ?