What is the equation of a line with a slope of 4 that passes through point (-2,5)? A y = -1/4x - 3 B y = -4x + 5 C y = 4x + 5 D y = 4x + 13

Solution given:

slope(m)=4

passes through (x',y')=(-2,5)

we have

equation of a line is:

y-y'=m(x-x')

substituting value we get

y-5=4(x-(-2))

y-5=4(x+2)

y-5=4x+8

y=4x+8+5

y=4x+13 is a required equation of a line.

sin3a=12/15

step-by-step explanation:

since one side was multiplied by 3 the other side must also be multiplied by 3.

it would take 7/10 of an hour too fill the pool.

step-by-step explanation: