Three friends, Ayyub, Bran and Curtis, each have some mini chocolate eggs. Bran has 1 more egg than Ayyub. Curtis has 50% more eggs than Bran. Altogether, Ayyub, Bran and Curtis have 48 chocolate eggs. Curtis gives eggs to each of Ayyub and Bran so that they all have the same number of eggs. Work out how many eggs Curtis gives away in total.

Step-by-step explanation:

x = eggs of Ayyub

y = eggs of Bran

z = eggs of Curtis

x + y + z = 48

y = x + 1

z = 1.5y = 1.5(x + 1)

now we are using the second and third equation in the first :

x + (x + 1) + 1.5(x + 1) = 48

x + x + 1 + 1.5x + 1.5 = 48

3.5x + 2.5 = 48

3.5x = 45.5

x = 45.5/3.5 = 13

y = x + 1 = 13 + 1 = 14

z = 1.5(x + 1) = 1.5(13 + 1) = 1.5×14 = 21

for all three friends to have the same number of eggs, we need to split 48 into 3 equal parts : a division.

48/3 = 16

so, everybody should end up with 16 eggs.

therefore Curtis gives away 21-16 = 5 eggs in total (3 to Ayyub, 2 to Bran).

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

51

step-by-step explanation:

73-22=51 the   mass number minus the amount of protons gives you the amount of neutrons