In 2000, the moose population in a park was measured to be 650. By 2010, the population was measured to be 750. Assume the population continues to change exponentially. Find a formula for the moose population, P(x), where x is the number of years after 2000

650 * (1.01)ˣ = P(x)

Step-by-step explanation:

One formula for exponential growth is

a*bˣ, where x represents time, a represents the initial amount, and b represents the growth rate. We have 650 as our initial amount because x is the number of years after 2000, and there are 650 moose in 2000. Then, we have

650 * b¹⁰ = 750 because, after 10 years, the moose population is 750. Solving for b, we have

750/650 = b¹⁰

(750/650)^(1/10) = b

= 1.01441296377 (can round this to 1.01)

Therefore, after x years, the moose population can be represented by the equation

650 * (1.01)ˣ

add all the numbers and check the ones place.

the answer is 486. as the ones place is more than 4, the estimation will be the next 10 ie, 490

answer: for each 3 girls there is 2 boys . 3: 2

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