How many solutions does x squared= 4x -5 have

There are no solutions

Two

Step-by-step explanation:

x^2 = 4x - 5 is equivalent to x^2 - 4x + 5 = 0 in standard quadratic form.

All quadratics have exactly two roots/solutions.

In this case the coefficients of the polynomial are 1, -4 and 5, and so the discriminant is b^2 - 4ac, or (-4)^2 - 4(1)(5), or 16 - 20 = -4.

Since the discriminant is negative, we conclude that this polynomial has two complex roots/solutions.

$79500

step-by-step explanation: