The line passes through the point (4,7) and has a slope that is reciprocal of the slope of the line y=1/3x+2 point slope form and slope intercept form pls

46.2+112.3

step-by-step explanation:

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

its kind of blurry. can you put a clearer pic?

step-by-step explanation: