Graph a sine function whose amplitude is 4, period is π , midline is y=−3, and y-intercept is (0, −3). The graph is not a reflection of the parent function over the x-axis. Use the sine tool to graph the function.

The first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.
PLZ GRAPH IT ON THIS GRAPH THAT I PROVIDED PLZZ HELP ASAP PLZZZ

The graph is shown below.

Explanation:

The midline is y = -3 and the y intercept is (0,-3). This is point A in the diagram below.

The period is pi units, which means that going from midline to peak (or valley) is 1/4 of this distance. So it's pi*(1/4) = pi/4 = 0.79 units approximately from x = 0 to x = 0.79; which is the x coordinate of point B. Point B is one of the infinitely many maximum points. Notice that the vertical distance from A to B is 4 units, which is the amplitude.

Extra info:

when studying polynomials, you often hear the terms zeros, roots, factors and x x the multiplicity of a zero is important because it tells us how the graph of the let's look at the graph of a function that has the same zeros

step-by-step explanation: