The force, F, acting on a charged object varies inversely to the square of its distance, r, from another charged object. When the two objects are 0.64 meters apart, the force acting on them is 8.2 Newtons. Approximately how much force would the object feel if it is at a distance of 0.77 meters from the other object?

Step-by-step explanation:

Varies inversely means a y=k/x situation.  So for your problem, we could say F=k/r2

F=k/r2 (definition of inverse relationship)

15.625 = k/(.4)2 (plugging in your given information)

k = 15.625*.16 = 2.5

Now you have an equation good for ANY distance/force relationship:

F = 2.5/r2

Now you can plug in the new information, and solve for your unknown:

F = 2.5/(.75)2 = 4.4444444444

Rounded to the nearest thousandth would be 4.444 Newtons (same units you solved for k with)

1.4

2.3

step-by-step explanation:

the formula for the constant of variation is

y= kx

divide each side by x

y/x =kx/x

y/x =k

we know a and y

1.   y/x = k

4/1 =4

check the other values to make sure they are the same

8/2 = 4   12/3 =4   and 16/4 =4  

the constant of variation is 4

2.   y/x = k

3/1 =3

check the other values to make sure they are the same

6/2 = 3   9/3 =3   and 12/4 =3  

the constant of variation is 3

the answer is 375 miles

step-by-step explanation: