Someone please help me I’m really struggling

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

the barter

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8

it would open into a square depending on the type of envelope i’m not sure about the second part