find all solutions of the equation 2sin2xcosx-sin2x=0 over the interval -pi/2 A = x=pi/6,0,pi/6,pi/2
B = -pi/3,-pi/4,pi/4, pi/3
C = -pi/4,-pi/6, pi/6, pi/4
D = x=-pi/3,0,pi/3,pi/2

i don't know, but that looks pretty bad. my school passed us unless we failed in all the subjects, but idk abt ur school's rules.

copyright potato 2019.

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5

there are no multiple choices

well, because the $0.25 is an added cost depending on how many minutes, the answer would be y = 30 + 0.25x.