A motorcycle is depreciating at 15% per year, every year. A student's $15,200 motorcycle depreciating at this rate can be modeled by the equation V(t) = 15,200(0.85). What is an equivalent
equation for this vehicle as a monthly depreciation and, using this equation, what is the motorcycle
worth (rounded to the nearest hundred dollar) 7 years after purchase?
Ov(t) = 15,200(0.8700)12, $13,800
Ov(t) = 15,200(0.9865), $4,900
Ov(t) = 15,200(1.15)-# $5,700
Ov(t) = 15,200(0.9865)12t, $4,900

correct answers below:

a is the correct

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .

a

step-by-step explanation: