Insert two rational number between 1.3 bar and 1.4 bar

General method:

Given numbers are 1.3 bar and 1.4 bar

Two rational numbers between them

= 1.3222... and 1.43333...

Mean Method:

Let X = 1.333... → → →eqn(i)

since the periodicity is 1 then multiply eqn(i) with 10

⇛10×X = 1.333...×10

⇛10X = 13.333... → → →eqn(ii)

Subtract eqn(ii)-eqn(i)

10X = 13.333...

X = 1.333...

(-)

9X = 12.000...

⇛9X = 12

⇛X = 12/9

⇛X = 4/3

and

Let X = 1.444... → → →eqn(i)

since the periodicity is 1 then multiply eqn(i) with 10

⇛10×X = 1.444...×10

⇛10X = 14.444...→ → →eqn(ii)

Subtract eqn(ii)-eqn(i)

10X = 14.444...

X = 1.444...

(-)

9X = 13.000...

⇛9X = 13

⇛X = 13/9

Now we have 12/9 and 13/9

The rational number between them by mean method (a+b)/2

⇛{(12/9)+(13/9)}/2

⇛(25/9)/2

⇛25/18

and Second rational number

⇛{(12/9)+(25/18)}/2

⇛{(24+25)/18}/2

⇛(49/18)/2

⇛49/36

Answer: The two rational numbers between them are 25/18 and 49/36.

also read similar questions: INSERT TWO RATIONAL NUMBERS BETWEEN 2 AND 3. How to find them?

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3