Please Help Tom says that he needs 6 rolls to obtain each possible outcome on a 6-sided die. On the fourth roll, he rolls his second "3”. Tom says that the die is loaded and that each outcome is not equally likely. Is Tom correct here? If you think Tom is incorrect, how many rolls should Tom make until he sees each number occurring about 1/6 of the time?

I think he is correct.

Step-by-step explanation:

I think he is correct because when you roll a die, it is 10 to 1 for the die to get the number you want.

Tom says that the dices outcome is NOT equally likely. When actually the outcome is equally likely.

On dice no two number repeat twice. So in this case every time he rolls the die he has the same chance of getting 3 than he does any other number.

So Tom is incorrect.

And for how many times it will take Tom for all the numbers to occur is all by luck and chance.

But each number is equally likely to come.

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*

i think it would be c

mark brainliest if im right

step-by-step explanation: