50 PT STATISTICS PLEASE HELP ASAP! You want to find out if the proportion of male college students who owned a pet during the past semester is greater than the proportion of female college students who owned a pet during the past semester. Out of a simple random sample of 300 female and 350 male college students, you find that 246 females and 312 males reported they had a pet the previous semester.

Which hypotheses should you test if pm and pf denote the proportions of all college males and females, respectively, who had a pet the previous semester?

H0: pm − pf = 0 versus Ha: pm − pf ≠ 0
H0: pm − pf = 0 versus Ha: pm − pf > 0
H0: pm − pf = 0 versus Ha: pm − pf < 0
H0: pm − pf > 0 versus Ha: pm − pf = 0
H0: pm − pf ≠ 0 versus Ha: pm − pf = 0

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation:

it is 28 degrees colder in detroit than philadelphia.

step-by-step explanation:

what number adds to 21

-7 + ? = 21

-7 + 28 = 21

hope it

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0