The zeros of a parabola are 6 and - 5. 11 (-1, 3) is a point on the graph, which equation can be sowed to find the value of a in the equation of the parabola?
O 3 = a(-1 + 6)(-1-5)
O 3= a(-1-6)(-1 + 5)
O -1 = a(3+6)(3-5)
O -1 = a(3-6)(3+5)

a

step-by-step explanation:

the answer is a

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)

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