A juggler tosses a ball into the air. The ball leaves the juggler's hand 5 feet above the ground and has an initial vertical velocity of 25 feet per second. The juggler catches the ball when it falls back down with a bucket 6 feet above the ground. Using the equation h= -16t2 + v0t + h0, where h represents the ending height, t is the time, v0 is the initial velocity, and h0 is the initial height, determine how long the ball is in the air.