The 20th term of the number sequence is 50
Write down the 21st term of the number sequence.

46

Step-by-step explanation:

126, 122, 118, 114

-4,-4,-4,-4

-4n+130

n=21

(-4*21)+130

-84+130

46

I hope this help too.

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The linear sequence 27, 25, 23, 21, 19... is an arithmetic progression with (-2) as the common difference.

The nth term of an arithmetic progression is an=a1+(n−1)da_n=a_1+(n-1)dan=a1+(n−1)d, where ana_nan is the nth term, a1a_1a1 is the first term, d is the common difference.

In our case, n=50,a1=27,d=−2n=50, a_1=27, d=-2n=50,a1=27,d=−2 , hence, we get

a50=27+49⋅(−2);a50=27−98=−71.a_{50}=27+49\cdot(-2);\\ a_{50}= 27-98=-71. a50=27+49⋅(−2);a50=27−98=−71.

The 50th term of this sequence is (-71).

d. 8

step-by-step explanation:

the given radical expression is:

we can rewrite this as:

we express as square numbers to get;

the exponents will now cancel out to give.

the correct answer is d