12. Solve these mixture applications: a. John is preparing 50 liters of a 25% saline solution. He only has 40% and a 10% solution
in his lab. How many liters of the 40% and how many liters of the 10% should she mix to
make the 25% solution?

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

goog may be able to you find that answer

300pi

step-by-step explanation: