What is the equation of a line written in point-slope form that passes through the point (2,-5) and is parallel to the line represented by 3x -2y = -14?

y=3/2x-8

Step-by-step explanation:

The slope of a line parallel to 3x-2y=-14 will be equivalent to the slope of this equation.

Rewrite the given equation in Slope/Intercept Form y=mx+b to get the slope m.

3x-2y=-14

2y=3x+14

divide both sides by 2 to solve for y.

y=(3x+14)/2

y=3/2x+7

slope m =3/2

Now that we have found the slope of our equation, we can put it into point-slope form : y-y1=m(x-x1) 2=x1 -5=y1

y--5=3/2(x-2)

y+5= 3/2x-3

subtract 5 from both sides to solve the equation for y

y=3/2x-8

hi,

3. 12.15, you are correct.

4.2.01, your first digit is correct,

hope this !

step-by-step explanation: 4 cause 2+2=4