Learning Task 2 B. Perform the indicated operations. Write your solution in the box below. Add Subtract: 1. (5x4 - 3x2 + 4) + (6x3 - 4x2 - 7) 6. (5x3 - 7x2 + 3x - 4) -(873 + 2x2 32-7) 2.-7x3y + 4x2y2 - 2 and 4x3y + 1 - 8x2y2 7. (2x2y - 5xy + 3y2 -- (7xy -- 672 - 5729) 3. (5 + 24y3 - 7y2) + (-6y3 + 7y2 + 5) 8. (9x5 - 623 + 712) - (773 4. (2xs - 6x3 - 12x2 - 4) + (-11x + 8x + 2x2 + 6) 9. Subtract 4x3.5x - 8 from 672 - 3x + 8 5. (3y5 - 2y + y* + 2y3 + 5) and (238 + 3y8 + 2+ 7) 10. (1.599 + 4.8y2 + 12) - (ya - 1.742 + 2y) Solution and Answer 67 + 2x2) -

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

if i put something wrong your not gonna like it so rather not say nothing.