Glven: A(0,6), B(6,6), C(6.0), D(0,0); ZDAB, ZABC, ZBCD, LCDA are right angles. Prove: ABCD is a square.
DA square on a coordinate plane
Proof:
.
AB = V (22 – 32)2 + (y2 – 1)? so AB =
.
• BC =
(22 – 22) + (92 - y.) so BC =
• CD= V(302 - 31) + (92 - 1)? So CD =
• DA= V(22 – 21)2 + (92 - y1) so DA =
.
Since ABCD has four
angles and four
sides, it is a square.

the equivalent expression are always the hardest ones but you look at the gcf also

step-by-step explanation:

hi there!

the answer will be d: 2

answer: 0.64

step-by-step explanation:

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb