Multiply the monomials:
(3/4)pq, (1/2)qr^2, -5q^2r^3 and -6r^5

Given monomials are (3/4)pq , (1/2)qr² , -5p²r³ and -6r⁵

On multiplying them then

⇛ [(3/4)pq]×[(1/2)qr²]×[-5p²r³]×[-6r⁵]

⇛ [(3/4)×(1/2)×(-5)×(-6)]×(pq×qr²×p²r³×r⁵)

⇛[(3×1×-5×-6)/(4×2)](p×p²)×(q×q)×(r²×r³×r⁵)

⇛ (90/8)×p³×q²×r¹⁰

Since a^m × a^n = a^(m+n)

⇛ (45/2)×p³×q²×r¹⁰

⇛( 45/2 ) p³q²r¹⁰

- [(3/4)pq]×[(1/2)qr²]×[-5p²r³]×[-6r⁵] = (45/2)p³q²r¹⁰

where is the rest of the

step-by-step explanation:

sine

step-by-step explanation: