Abox of marbles can be shared equally among 6, 7, or 8 students with 4 marbles left over each time what is the least possible number of marbles in the box

So the problem is, what is the least number than can be divided into 6, 7 and 8?

The numbers have only one non-1 divisor in common: both 6 and 8 are divisible by 3. 

So for our drives we can "delete" one 2 and ask:

what is the smallest number than can be divided into 3,7 and 8 ?

There are no more divisors in common, so we just have to multiply them: 3*7*8 = 21*8=168

and the 4 marbles "extra"? We add them to this sum. 

So, the smallest possible number in the box is 168 + 4 = 172.

step-by-step explanation:

hi there!

the answer will be d: 2