Write an equation of the line that passes through (4, -5) and is perpendicular to the line y = 2x +3

Hello there!

We are given the equation of the line

y=2x+3

What's the equation of the line perpendicular to it?

Perpendicular lines have slopes that are opposite reciprocals. This means we take a number, make it negative, and flop it over.The slope of the line perpendicular to the given line is -1/2.Now that we have the slope of the line and a point that the line passes through, we can find the equation of the line.Write it in Point-Slope form:y-y1=m(x-x1)y-(-5)=-1/2(x-4)y+5=-1/2(x-4)y+5=-1/2x+2y=-1/2x+2-5y=-1/2x-3

Therefore, this is the equation. Hope it helps. Good luck.

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Arhombus is a quadrilateral.