Prove: AC bisects DAB and BCD Identify the missing statement and reason in the proof.

Given rhombus ABCD with diagonal AC , it follows from the definition of a rhombus that AB BC CD AD. By the reflexive property of congruence, AC = AC . So, DAC = BAC by the ?
. Since corresponding parts of congruent triangles are congruent, DAC = ? and DCA = ?. So, by the definition of segment bisector AC bisects DAB and BCD .

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step-by-step explanation:

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.

translate k to n and reflect across the line containing jk.