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Mathematics, 06.12.2021 18:00 krazyapril4601

Solve: 1.Square both sides of the equation.
2.Expand the left side.(3 βˆ’ k)(3 βˆ’ k) = 3k + 1
3.Multiply9 βˆ’ 6k + k2 = 3k + 1
4.Write the quadratic equation in standard form. k2 βˆ’ 9k + 8 = 0
5.Factor the quadratic equation.(k βˆ’ 8)(k βˆ’ 1) = 0
6.Use the zero product property.
The solutions to the quadratic equation are
.

The true solution(s) to the radical equation

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Answers: 2

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Solve: 1.Square both sides of the equation.
2.Expand the left side.(3 βˆ’ k)(3 βˆ’ k) = 3k + 1
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