Solve the system using substitution 4x+3y=23 x-5=0

y=1, x=5

Step-by-step explanation:

Since x-5=0 is given already, give the x a value and switch the 5 to the other side x-5=0 > x=5

Now we have a value for x, so plug x into the original equation,

4(5)+3y=23,

20+3y=23

Subtract both sides by 20

20-20+3y=23-20

3y=3

dvide both sides by 3

y=1

use the value for x we got earlier

y=1, x=5

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3