Pairs of markings a set distance apart are made on highways so that police can detect drivers exceeding the speed limit. Over a fixed distance, the speed R
varies inversely with the time T. In one particular pair of markings, R is 59 mph
when T is 4 seconds. Find the speed of a car that travels the given distance in 5
seconds.

Please answer!!!

R = k(1/T) = k/T

when R = 60, T = 8

60 = k/8

k = 480

R = 480/T

so when T = 6

R = 480/6 = 80 mph

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)

a

step-by-step explanation:

the denominator cannot be the same as one of the factors.

8 denominator times 2 denominator = 16

and 7 numerator time 11 = 77

77/16= 77/16 ( they cannot be further simplified)