Use your knowledge about parentheses and substitution to solve the following: q = 1; r = 2; s = 3; t = 4; x = 5; y = 6

7. 2(x + 4) + 10 =

8. 3(6x) + 4 =

9. 10(xy) =

10. 5(x + y) =

11. 2(rs) + 4(x)

12. 2(q) + 2(x + t) =

13. 6(7t + 4s) =

14. 9(10x) + 10y =

15. 2x(xy) =

16. r(s)(t) =

17. (r)(s)(t)(x)(y) =

18. (7x + 2Y) =

16. r(s)(t) =

r=2, s=3, t=4

(2)(3)(4)=

             (2*3) = 6  ---> 6(4) = 24

final: 24

17. (r)(s)(t)(x)(y) =

r = 2, s = 3, t = 4, x = 5, y = 6

(2)(3)(4)(5)(6)

2*3=6

      6*4=24

            24*5= 120

                     120*6=720

final: 720

18. (7x + 2Y) =

x = 5, y = 6

rewrite--->        = [7(5) + 2(6)]

[35 + 12] = 47

final: 47

hope this helpsss sorry took a while LOL

Step-by-step explanation:

q = 1; r = 2; s = 3; t = 4; x = 5; y = 6

no

step-by-step explanation:

answer: the answer is e

step-by-step explanation: