Heights (cm) and weights (kg) are measured for 100 randomly selected adult males, and range from heights of 136 to 194 cm and weights of 37 to 150 kg. Let the predictor variable x be the first variable given. The 100 paired measurements yield x = 167.72 cm, y = 81.43 kg, r = 0.339, P-value = 0.001, and ŷ - - 106+ 1.13x. Find the best predicted value of ý (weight) given an adult male who is 162 cm tall. Use a 0.01 significance level . kg. The best predicted value of y for an adult male who is 162 cm tall is (Round to two decimal places as needed.)

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

the answer is 1/4

step-by-step explanation:

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