The heights of male students are normally distributed with a mean of 160 cm and a standard deviation of 6 cm.
Find the percentage of male students who are less than 148 cm. Round your answers to the nearest
hundredth

2.28%

Step-by-step explanation:

As this is normally distributed, we can use z scores to find the percentage.

First, find the z-score for 148.

The z-score that you get is:

(148-160)/2=2

As we see that z=2, we can use a calculator or a z-score chart to find the percentage less than a z score of 2.

I used my chart and found: 2.28%

6mm

Step-by-step explanation:

Comment of the

the line of

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.