A bicycle manufacturing company makes a particular type of bike. Each chad bike requires 4 hours to build and 4 hours to set. Each adet bike requires 6 hours to build and 4 hours to test with the number of workers, the company is able to have up to 120 hours of building time and 100 hours of testing time for a week. Ifc represents child bikes and a represents adatkes, can the company build Schildbikes and 15 adut bikes in a
O No, because the bike order does not meet the restrictions déc+62 s 120 and 4+48 100
O No, because the bkce order does not meet the restrictions of 4c + las 120 and 6c • tas 100
Yes, because the border moes the restrictions of cas 120 and 4C +100
Yes, because the bike onder meets the restrictions of cas 120 and 6c .tas 100

15 units use socratic

step-by-step explanation: 15 units

complete the steps to find the area of the trapezoid.

area of rectangle = 256   square units

area of triangle 1 = 24  square units

area of triangle 2 = 16  square units

area of triangle 3 =   96 square units

area of trapezoid = 120  square units

step-by-step explanation:

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.