What is an equation of the line that passes through the points (4, 3) and (7, 3)?

y = 3

Step-by-step explanation:

We can see that the y coordinate is 3 the same for both points so we have a horizontal line that has the equation y = 3

or if we can't see right away you can solve for the equation of the line using the -General equation of a line in a slope intercept form is:

y = mx+ b , where m is the slope and b is the y-intercept and what we need to find to complete the equation

For the points (x1 = 4, y1 = 3) and (x2 = 7, y2 = 3)

m= (y2-y1)/ (x2-x1) = (3-3)/ (7-4) = 0/3 = 0

y = 0·x+ b

y = b = 3

so the equation going trough points  (4, 3) and (7, 3) has the equation y = 3

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m