Proof #1 1. space space open parentheses x close parentheses space open parentheses R x superset of T x close parentheses 2. space space R a space space space space space space space space space space space space space space space space divided by space open parentheses there exists x close parentheses space open parentheses T x space times space R x close parentheses

30 units^2

step-by-step explanation:

area is l × w

the length is 3

and the width is 10

3 × 10= 30 units squared

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)

h/o/e/s mad

step-by-step explanation:

si si si