Mathematics, 03.12.2021 05:30 kalithekittenqueen
Suppose that in college you were so good at math…especially algebra and exponential functions…that you
graduated with honors and got a killer job with high pay. Remember, math skills are in high demand these days and
with math you can do anything. Well, anyway, you are travelling down a county road and a truck hauling
construction debris loses a board with a nail sticking straight up and you run over it…the board…not the truck.
Since you have such a high paying job due to your math skills you were able to afford a car that was good at math
also. The car’s tire pressure sensors immediately calculate the air loss in the punctured tire can be modeled by the
function P(t) = 32e^(-.2t) ( 32 times e to the negative point 2 times t ), where P(t) gives the tire’s air pressure in
pounds per square inch and t is time in minutes.
Being a highly informed citizen, in that you felt the respons
Answers: 1
Mathematics, 21.06.2019 15:30
State whether weight is a function of height for the six students and explain. a. yes, height is a function of weight because two students weigh 165 pounds but have different heights. b. no, height is not a function of weight because two students weigh 165 pounds but have different heights. c. yes, weight is a function of height because for each value of height there is one corresponding value of weight. d. no, weight is not a function of height because there is not enough data to determine a function.
Answers: 1
Mathematics, 21.06.2019 19:00
Simplify. −4x^2 (5x^4−3x^2+x−2) −20x^6−12x^4+8x^3−8x^2 −20x^6+12x^4−4x^3+8x^2 −20x^8+12x^4−4x^2+8x −20x^6+12x^4+4x^3−8x^2
Answers: 1
Mathematics, 21.06.2019 20:20
Drag the tiles to the correct boxes to complete the pairs. not all tiles will be used. identify the domain for each of the given functions.
Answers: 1
Mathematics, 21.06.2019 20:30
Does the function satisfy the hypotheses of the mean value theorem on the given interval? f(x) = 4x^2 + 3x + 4, [−1, 1] no, f is continuous on [−1, 1] but not differentiable on (−1, 1). no, f is not continuous on [−1, 1]. yes, f is continuous on [−1, 1] and differentiable on (−1, 1) since polynomials are continuous and differentiable on . there is not enough information to verify if this function satisfies the mean value theorem. yes, it does not matter if f is continuous or differentiable; every function satisfies the mean value theorem.
Answers: 1
Suppose that in college you were so good at math…especially algebra and exponential functions…that y...
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