The number of values of k for which the linear equation 4x ky 2z=0;kx 4y z=0; 2x 2y z=0 possess a non-zero solution is: 1. 1 2. Zero 3. 3 4. 2.

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead

no

step-by-step explanation:

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5

agree

step-by-step explanation: