Given the equation: x^2+6x+8=0 By using the equation editor or uploading a picture, rewrite the equation in the form:
(x-h)^2=k

Apolynomial function has a root of –6 with multiplicity 1, a root of –2 with multiplicity 3, a root of 0 with multiplicity 2, and a root of 4 with multiplicity 3. if the function has a positive leading coefficient and is of odd degree, which statement about the graph is true?

Ineed i been stuck on this question since yesterday

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