Data were recorded for the temperature, in degrees Celsius, of a cup of coffee over a 30-minute period. Gwen the regression equation, in(Temp) = 4,20 - 0.923 (Time), what is the predicted temperature after 5 minutes?

5944°C

64.26°C

65.17°C

66.69°C

70

step-by-step explanation:

2*5=10

4*15=60

60+10=

70

%40

step-by-step explanation:

one set of data has more variation than the other. hope this !

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.