Given: Isosceles trapezoid EFGH Prove: ΔFHE ≅ ΔGEH

Trapezoid E F G H is shown. Diagonals are drawn from point F to point H and from point G to point E. Sides F G and E H are parallel.

It is given that trapezoid EFGH is an isosceles trapezoid. We know that FE ≅ GH by the definition of
. The base angle theorem of isosceles trapezoids verifies that angle
is congruent to angle
. We also see that EH ≅ EH by the
property. Therefore, by
, we see that ΔFHE ≅ ΔGEH.

.5 lb

step-by-step explanation:

12 in / 6 in =2 in

.25 x 2 = .5 lb

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step-by-step explanation:

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b

we have the parent function given by,

1. the function is translated 5 units to the left.

so, we get,   becomes

2. the function is translated 5 units to the right.

so, we get,   becomes

3. the function is translated 5 units upwards.

so, we get,   becomes

4. the function is translated 5 units downwards.

so, we get,   becomes

5. the function is reflected across x-axis.

so, we get,   becomes

6. the function is reflected across y-axis.

so, we get,   becomes .

step-by-step explanation:

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