The sides of a triangle are in the ratio 3, 4, 5. State whether the triangle is right angled or not.

If the sides of a triangle are in the ratio 3:4:5, prove that it is a right-angled triangle.

Step-by-step explanation:

In order to prove that the triangle is a right-angled triangle or not, take the ratio as the length of the sides then consider the triangle to be a right-angled triangle, then prove the Pythagoras theorem. If the sides satisfy the Pythagoras theorem, then it’s a right-angled triangle otherwise, it’s not a right-angled triangle.

We are given the sides of a triangle whose ratio is 3:4:5.

Considering the sides to be 3x,4x,5x.

Since, we know that the length of hypotenuse is always greater than the other two sides, so we are taking the hypotenuse to be 5x and other remaining sides to be 3x and 4x.

We are only considering that the given triangle is a right-angled triangle. For that we need to prove that the sides follow Pythagoras theorem.

So, for Pythagora's theorem, we know that the sum of the square of the base side and square of the height side is equal to the square of the hypotenuse.

Squaring the base side 4x, we get:

(4x)2=16x2 …….(1)

Similarly, squaring the height side 3x, we get:

(3x)2=9x2 …….(2)

Squaring the hypotenuse side 5x, and we get:

(5x)2=25x2 …….(3)

Taking the sum of (1) and (2):

16x2+9x2=25x2, which is equal to the equation (3).

That means the sum of the square of base and the square of height is equal to the square of hypotenuse, that satisfies the Pythagoras theorem, that implies the triangle ABC is actually a right-angled triangle, which is right-angled at B. And this proves our consideration to be true.

it is a right triangle

Step-by-step explanation:

If the triangle is a right triangle, it will meet the Pythagorean theorem

a^2 + b^2 = c^2

3^2+4^2 = 5^2

9+16=25

25=25

This is true so it is a right triangle

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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