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Mathematics, 30.11.2021 05:40 jmolina57

Helpp , im taking a test and I dont get the question An object Is launched at 19.6 meters per second (m/s) from a 58.8-meter tall platform. The equation for the object's heights at time t seconds after launch is s(t) = -4.9t² +19.6t+58.8, where s is in meters. How high will the object be after 3 seconds?

98.40 feet
333.69 feet
73.5 feet
161.7 feet

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