At a certain theater 4 adult tickets and 2 children's tickets cost $36.50. Three adult tickets and 5 children's tickets cost $38.75. Which
system of equations could be used to determine the cost of one adult
ticket, a, and one child's ticket, c?
A. 4a +2c= 36.50
3a + 5c = 38.75
B. 7a+ 7 = 14
a+b= 75.2
C. 7a = 36.50
5a + 7c = 38.75
D. 4a + 2c = 38.75
За + 5c = 36.50

And how much is an adult ticket?how much is an child ticket?

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation: