At a particular time, a tree casts a shadow 17 m long on horizontal ground. At the same time, a vertical pole 3 m high casts a shadow 4 m long. Calculate the height of the tree to the nearest tenth of a meter.

center= (-2,0)

radius= sqrt2/2

step-by-step explanation:

thus, the first answer choice, y = sec x, is the correct one

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube

step-by-step explanation: