To reach his office on time, Mr Chin usually drives to work at an average speed of 75 km/h. However, if Mr Chin increases his average driving speed by 5 km/h, he will reach his office 10 minutes earlier. If the distance Mr Chin needs to travel to reach his office is represented by x km, form an equation in x and solve for x.

 x = 200 km

Step-by-step explanation:

Distance(x) = Speed(s) x Time(t)

t is in hours

x=s*t

At 75km/h:  75*t = x

At 80km/h:  80*(t-(10/60)) = x  [the -(10/60) is the 10 minutes saved, in hours]

We know the distance, x, is the same, so we can set these equal to each other:

75*t = 80*(t- (10/60))

75*t = 80*t - 13.3333

-5*t = -13.3333

t = 2 2/3 hours

Both situations should give the same distance with 2 2/3 and 2 2/3 - :

x = (75 km/hr) x ( 2 2/3 hr)= 200 km

x = (80 km/hr) x (2 2/3 - 1/6 hr) = 200 km

if you need just tell me and i will come to the rescue.

step-by-step explanation:

in mathematics, a constraint is a condition of an optimization problem that the solution must satisfy. there are several types of constraints—primarily equality constraints, inequality constraints, and integer constraints. the set of candidate solutions that satisfy all constraints is called the feasible set.

hoped i'm right lol