If f is an always positive, differentiable function and y = ln(f(sin x)), what is y’ when x=4 ?

cos(4) f'(sin 4)/f(sin 4) is y' at x=4

Step-by-step explanation:

We can't actually find the numerical value for this without more information.

We are given:

y=ln(f(sin x))

This is equivalent to

e^y=f(sin x)

Differentiate both sides:

y' e^y=cos(x) f'(sin x)

Divide both sides by e^y:

y' =cos(x) f'(sin x)/e^y

Rewrite in terms of x using that e^y=f(sin x):

y' =cos(x) f'(sin x)/f(sin x)

Now replace x with 4:

cos(4) f'(sin 4)/f(sin 4) is y' at x=4

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph

the answer is a.

step-by-step explanation:

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